1/5x^2(20x^2-10x+4)

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Solution for 1/5x^2(20x^2-10x+4) equation: 


x in (-oo:+oo)

(1/5)*x^2*(20*x^2-(10*x)+4) = 0

(1/5)*x^2*(20*x^2-10*x+4) = 0

1/5*x^2*(20*x^2-10*x+4) = 0

20*x^2-10*x+4 = 0

2*(10*x^2-5*x+2) = 0

10*x^2-5*x+2 = 0

DELTA = (-5)^2-(2*4*10)

DELTA = -55

DELTA < 0

2 = 0

1/5*2*x^2 = 0

1/5*x^2 = 0 // : 1/5

x^2 = 0

x = 0

x = 0

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